Deletions:
elbobocvi
Additions:
elbobocvi
Additions:
How to count the number of 1's (set bits) in a given number ?
There are many ways you can do this, below are a few naive methods for the beginners:
Please refer to this site
Bit Twiddling Hacks∞ to learn many other methods to count bits, which are much more efficient than the above methods, and they manipulate bits at the lowest level.
Deletions:
Counting the number of bits that are set in a given number
There are many ways you can do this.
All the methods that I have mentioned here are naive attempts and are very easy to understand. Please refer to this site
Bit Twiddling Hacks∞ to learn more about manipulating bits at the lowest level.
Additions:
int count= 0;
while(num){
count += num & 1;
num
= 1;
}
return count;
Deletions:
int count= 0;
while(num){
count += num & 1;
num
= 1;
}
return count;
Additions:
int count= 0;
while(num){
count += num & 1;
num
= 1;
}
return count;
} %%
Deletions:
int count=num&1;
while(num
=1){
(num&1)?++count:count;
Additions:
Deletions:
Additions:
All the methods that I have mentioned here are naive attempts and are very easy to understand. Please refer to this site
Bit Twiddling Hacks∞ to learn more about manipulating bits at the lowest level.
Deletions:
All the methods that I have mentioned here are naive attempts and are very easy to understand. Please refer to this site
Bit Twiddling Hacks∞ to learn more about bit twiddling hacks.
Additions:
Counting the number of bits that are set in a given number
Additions:
while(num>>1){
(num&1)?++count:count;
(c)
Here is how you can do it in C++ using the bitset class provided in the STL.
All the methods that I have mentioned here are naive attempts and are very easy to understand. Please refer to this site
Bit Twiddling Hacks∞ to learn more about bit twiddling hacks.
Deletions:
while((num
1) & 1){
count++;
All the methods that I have mentioned here are naive attempts. Please refer to this site to learn more about bitt twiddling hacks.
Bit Twiddling Hacks∞
Additions:
int countBits(int num){
std::bitset<sizeof(int)*8> temp(num);
return temp.count();
Deletions:
Additions:
Deletions:
bitset<sizeof(int)*8> temp(num);
return temp.count();
Additions:
%%(cpp)
Deletions:
%%(cpp;1)
This is another question that confounds most of the newbies in Orkut and they end up confusing themselves and the others.
There are many ways you can do this.
int countBits(unsigned num){
bitset<sizeof(int)*8> temp(num);
return temp.count();
}